函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 06:52:56
x){ھ
iFřyM4L]0S6x>iÞ$铡KΆ\+PRa
@V29X#PPIQ,#j:^|gk?ݳn^{ְŖfL~>=B';vE6yv
函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域
函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域
函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域
f(x)=2sin(x+π/4)sin(x-π/4)+sin2x
=2sin(x+π/4)sin(-π/2+x+π/4)+sin2x
=-2sin(x+π/4)cos(x+π/4)+sin2x
=-sin(2x+π/2)+sin2x
=-cos2x+sin2x
=√2sin(2x-π/4)
所以由正弦型函数的性质易知:
函数f(x)的值域为[-√2,√2]
函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域
傅里叶级数作图f(x)=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si
已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4)
设f(x)=4cos(ωx-π/6)sinωx-cos(2ωx+π),其中ω>0,求函数y=f(x)的值域,请看问题补充f(x)=4cos(ωx-π/6)sinωx-cos(2ωx+π) =4(coswxcosπ/6+sinwxsinπ6)sinwx+cos2wx =2√3sinwxcoswx+2sin²wx+cos2wx =√3si
已知函数f(x)=cos2x/[sin(π/4-x)]
f(x)=sin(x+π/4)是什么函数
设函数 f(x)=sin(2x+y),(-π
设函数f(x)=sin(2x+φ)(-π
设函数f(x)=sin(2x+φ)(-π
设函数f x=SIN(2X+φ)(-π
设函数f(x)=sin(2x+φ)(-π
设函数f(x)=sin(2x+φ)(-π
已知函数F(X)=SIN(2X+φ)(-π
设函数f(x)=sin(2x+φ)(-π
设函数f(x)=sin(2x+φ)(-π
设函数f(x)=sin(2x+ φ)(-π
设函数f(x)=sin(2x+φ)(-π
函数f(x)=sin(2x+a) -π