如图,直线AB,CD与直线EF相交与点P,Q,∠APE=∠CQE,∠APQ=2∠CQE,求∠APQ、∠CQE、∠BPF的度数
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![如图,直线AB,CD与直线EF相交与点P,Q,∠APE=∠CQE,∠APQ=2∠CQE,求∠APQ、∠CQE、∠BPF的度数](/uploads/image/z/12645340-52-0.jpg?t=%E5%A6%82%E5%9B%BE%2C%E7%9B%B4%E7%BA%BFAB%2CCD%E4%B8%8E%E7%9B%B4%E7%BA%BFEF%E7%9B%B8%E4%BA%A4%E4%B8%8E%E7%82%B9P%2CQ%2C%E2%88%A0APE%EF%BC%9D%E2%88%A0CQE%2C%E2%88%A0APQ%EF%BC%9D2%E2%88%A0CQE%2C%E6%B1%82%E2%88%A0APQ%E3%80%81%E2%88%A0CQE%E3%80%81%E2%88%A0BPF%E7%9A%84%E5%BA%A6%E6%95%B0)
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如图,直线AB,CD与直线EF相交与点P,Q,∠APE=∠CQE,∠APQ=2∠CQE,求∠APQ、∠CQE、∠BPF的度数
如图,直线AB,CD与直线EF相交与点P,Q,∠APE=∠CQE,∠APQ=2∠CQE,求∠APQ、∠CQE、∠BPF的度数
如图,直线AB,CD与直线EF相交与点P,Q,∠APE=∠CQE,∠APQ=2∠CQE,求∠APQ、∠CQE、∠BPF的度数
没图.
图呢?没图怎么解