求 y=sin(-3x+π/4)的单调递增区间,遇到问题如下,我一开始是直接用2kπ -π/2 ≤ -3x+ π/4 ≤ π/2 + 2kπ求的,不知是否正确.然后老师说要把原式变成 y= -sin(3x-π/4),再有 2kπ+ π/2 ≤ 3x-π/4 ≤ 3π/2 +
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![求 y=sin(-3x+π/4)的单调递增区间,遇到问题如下,我一开始是直接用2kπ -π/2 ≤ -3x+ π/4 ≤ π/2 + 2kπ求的,不知是否正确.然后老师说要把原式变成 y= -sin(3x-π/4),再有 2kπ+ π/2 ≤ 3x-π/4 ≤ 3π/2 +](/uploads/image/z/12645651-3-1.jpg?t=%E6%B1%82+y%3Dsin%EF%BC%88-3x%2B%CF%80%2F4%EF%BC%89%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4%2C%E9%81%87%E5%88%B0%E9%97%AE%E9%A2%98%E5%A6%82%E4%B8%8B%2C%E6%88%91%E4%B8%80%E5%BC%80%E5%A7%8B%E6%98%AF%E7%9B%B4%E6%8E%A5%E7%94%A82k%CF%80+-%CF%80%2F2+%E2%89%A4+-3x%2B+%CF%80%2F4+%E2%89%A4+%CF%80%2F2+%2B+2k%CF%80%E6%B1%82%E7%9A%84%2C%E4%B8%8D%E7%9F%A5%E6%98%AF%E5%90%A6%E6%AD%A3%E7%A1%AE.%E7%84%B6%E5%90%8E%E8%80%81%E5%B8%88%E8%AF%B4%E8%A6%81%E6%8A%8A%E5%8E%9F%E5%BC%8F%E5%8F%98%E6%88%90+y%3D+-sin%EF%BC%883x-%CF%80%2F4%EF%BC%89%2C%E5%86%8D%E6%9C%89+2k%CF%80%2B+%CF%80%2F2+%E2%89%A4+3x-%CF%80%2F4+%E2%89%A4+3%CF%80%2F2+%2B)
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