(2x-3)/(x+5)≤0
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/20 22:15:38
x)05ר6|Թ&HSPΆH
_HU Bœv>էkkj_\g2 '/
(2x-3)/(x+5)≤0
(2x-3)/(x+5)≤0
(2x-3)/(x+5)≤0
(2x-3)/(x+5)≤0 (2x-3)(x+5)≤0 -5≤x≤3/2 x不等于-5!-5
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
3≤|8-x| |x+1|>2-x |x+3|7|x+1| x^2-6|x|+9>0 |x-1|+|x+2|≥5 (1)方法
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
(2x-3)/(x+5)≤0
两道有关符号问题题目|x=2|+|x-3| x+2=0 x=-2 x-3=0 x=3x<-2-x-2-x-3=-2x=1x>3x+2+x-3=2x-1-2≤x≤3x=2-x+3=5|x-1|+|x+1| x-1=0 x=1 x+1=0 x=-1 x≤-1-x+1-x+1=2-2xx>1x-1+x+1=2x-1<x≤11-x+x+1=2两道题目都是零点
如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值,
(x-2)(x-3)/(x+5)(x-7)>0(x-2)(x-3)(x+2)(x+3)>0
5(x的2次方+X-3)-4x(6+x)+x(-x+4)=0
1.(7x-1/5)-3≤2x-52.x^2-x-6≤0
{x+1>0,3x>0的解集,{-3x≤0,5x-2
已知实数x满足5x*x-3x-5=0,求代数式5x*x-2x-[1/5x*x-2x-5]的值.
已知实数x满足5x*x-3x-5=0,求代数式5x*x-2x-1/5x*x-2x-5的值.
若x^3+x^2+x+1=0,求代数式1+x+x^2+x^3+x^4+x^5+...+x^2006+x^2007的值
5X+125≤0 6-2X>0 -X+1>7X-3
若x*x+x+1+0,求x^7+2x^6+x^5+x^4+x^3+x*x+1的值
已知集合A={x/(x+3)(x-5)≤0},B={x/m-2
x²-5x+6≥0 为什么x≥3,x≤2
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4