解算式:2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)加急
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/29 00:26:42
![解算式:2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)加急](/uploads/image/z/12654691-43-1.jpg?t=%E8%A7%A3%E7%AE%97%E5%BC%8F%EF%BC%9A2%2F%28x%2B1%29%28x%2B3%29%2B2%2F%28x%2B3%29%28x%2B5%29%2B.%2B2%2F%28x%2B2001%29%28x%2B2003%29%E5%8A%A0%E6%80%A5)
x){|uӟgF&0sASMm= ,
5v-xְ&HCڡ&PAd86IA!V;ʂ
``Cb!(MQ@Aa|]Xh+QL r0@a ~
解算式:2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)加急
解算式:2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)
加急
解算式:2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)加急
2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)
=[1/(x+1) -1/(x+3)]+[1/(x+3) -1/(x+5)]+.+[1/(x+2001) -1/(x+2003)]
= 1/(x+1) - 1/(x+2003)
= [(x+2003)-(x+1)]/[(x+1)(x+2003)]
= 2002/[(x+1)(x+2003)]