X^3+4X^2-7X-10

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X^3+4X^2-7X-10
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X^3+4X^2-7X-10
X^3+4X^2-7X-10

X^3+4X^2-7X-10
X^3+4X^2-7X-10
（x³-2x²）+6x²-7x-10
=x²(x-2)+(6x+5)(x-2)
=(x-2)(x²+6x+5)
=(x-2)(x+1)(x+5)
如果 X^3+4X^2-7X-10 =0
那么x=-1,x=-5,x=2

X^3+4X^2-7X-10=0
首先向办法分解因式
（x³-2x²）+6x²-7x-10
=x²(x-2)+(6x+5)(x-2)
=(x-2)(x²+6x+5)
=(x-2)(x+1)(x+5)

即：(x-2)(x+1)(x+5)=0
所以x=-1或者x=-5或者x=2

是求值，，还是分解因式
分解因式：
（x³-2x²）+6x²-7x-10
=x²(x-2)+(6x+5)(x-2)
=(x-2)(x²+6x+5)
=(x-2)(x+1)(x+5)

求值：
X^3+4X^2-7X-10 =0
x=-1或x=-5或x=2

应该是X^3+4X^2-7X-10=0的解吧？
X^3+4X^2-7X-2-8=（X^3-8）+（4X^2-7X-2）=(x-2)(x^2+2x+4)+(x-2)(4x+1)=(x-2)(x^2+6x+5)=(x-2)(x+1)(x+5)=0
x1=2,x2=-1,x3=-5

X^3+4X^2-7X-10
（x³-2x²）+6x²-7x-10
=x²(x-2)+(6x+5)(x-2)
=(x-2)(x²+6x+5)
=(x-2)(x+1)(x+5)
如果 X^3+4X^2-7X-10 =0
那么x=-1,x=-5,x=2

分解因式，得 (x+1)(x+5)(x-2)=0 x=-1或-5或2

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