已知在三角形ABC中,AB=AC,角BCA=90度,E、F都是BC上点,且角EAF=45度,求证:BE、EF、FC构成一个直角三角形.已知在三角形ABC中,AB=AC,角BAC=90度,E、F都是BC上点,且角EAF=45度,求证:BE、EF、FC构成一个
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 10:54:59
![已知在三角形ABC中,AB=AC,角BCA=90度,E、F都是BC上点,且角EAF=45度,求证:BE、EF、FC构成一个直角三角形.已知在三角形ABC中,AB=AC,角BAC=90度,E、F都是BC上点,且角EAF=45度,求证:BE、EF、FC构成一个](/uploads/image/z/12679772-68-2.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CAB%3DAC%2C%E8%A7%92BCA%3D90%E5%BA%A6%2CE%E3%80%81F%E9%83%BD%E6%98%AFBC%E4%B8%8A%E7%82%B9%2C%E4%B8%94%E8%A7%92EAF%3D45%E5%BA%A6%2C%E6%B1%82%E8%AF%81%EF%BC%9ABE%E3%80%81EF%E3%80%81FC%E6%9E%84%E6%88%90%E4%B8%80%E4%B8%AA%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2.%E5%B7%B2%E7%9F%A5%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%EF%BC%8CAB%3DAC%2C%E8%A7%92BAC%3D90%E5%BA%A6%EF%BC%8CE%E3%80%81F%E9%83%BD%E6%98%AFBC%E4%B8%8A%E7%82%B9%EF%BC%8C%E4%B8%94%E8%A7%92EAF%3D45%E5%BA%A6%EF%BC%8C%E6%B1%82%E8%AF%81%EF%BC%9ABE%E3%80%81EF%E3%80%81FC%E6%9E%84%E6%88%90%E4%B8%80%E4%B8%AA)
xmOPǿ
!Yl$ۄa
c1GA06P4@`amW|OW&:mҦ=MO8M?P+Z[vS(D!шhu#sԜ3BverzQsW8Y=6Lٕ]`j .N]!D@@" AK?Ay6 ':8t&?$wỳ#3G:CC,KD2H
2I'SDpGFd@D3dpH#aĦ.Z""+`'