已知(a+2)²+|a+b+5|=0,求[3a²b-(2ab-a²b)-4a²]-ab的值
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已知(a+2)²+|a+b+5|=0,求[3a²b-(2ab-a²b)-4a²]-ab的值
已知(a+2)²+|a+b+5|=0,求[3a²b-(2ab-a²b)-4a²]-ab的值
已知(a+2)²+|a+b+5|=0,求[3a²b-(2ab-a²b)-4a²]-ab的值
由(a+2)²+|a+b+5|=0,得
a=-2,b=-3
[3a²b-(2ab-a²b)-4a²]-ab
=(4a²b-2ab-4a²)-ab
=4a²b-3ab-4a²
=4*4*(-3)-3*(-2)*(-3)-4*9
=-48-18-36
=-102
a=-2,b=-3,带入求解即可