先化简,再求值(a+b)²+(a+b)(2a-b)-3a²,其中a=-2-√3,b=√3-2
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先化简,再求值(a+b)²+(a+b)(2a-b)-3a²,其中a=-2-√3,b=√3-2
先化简,再求值(a+b)²+(a+b)(2a-b)-3a²,其中a=-2-√3,b=√3-2
先化简,再求值(a+b)²+(a+b)(2a-b)-3a²,其中a=-2-√3,b=√3-2
原式=a²+2ab+b²+2a²+ab-b²
=3a²+3ab
=3(-2-√3)²+3(-2-√3)(√3-2)
=3(7+4√3)+3(4-3)
=24+12√3