因式分解 1：（x+y)(x+y)-(x+y)^2=?2：(x+y))^2+mx+my=?3：a(x-a)(x+y)^2-b(x-a)^2(x+y)=?

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因式分解 1：（x+y)(x+y)-(x+y)^2=?2：(x+y))^2+mx+my=?3：a(x-a)(x+y)^2-b(x-a)^2(x+y)=?
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因式分解 1：（x+y)(x+y)-(x+y)^2=?2：(x+y))^2+mx+my=?3：a(x-a)(x+y)^2-b(x-a)^2(x+y)=?
因式分解 1：（x+y)(x+y)-(x+y)^2=?2：(x+y))^2+mx+my=?3：a(x-a)(x+y)^2-b(x-a)^2(x+y)=?

因式分解 1：（x+y)(x+y)-(x+y)^2=?2：(x+y))^2+mx+my=?3：a(x-a)(x+y)^2-b(x-a)^2(x+y)=?
这个不是很难丫
第一题
（x+y)(x+y)-(x+y)^2
=（x+y)(x+y)-(x+y)(x+y)
=0
我想你第一题打错题目了吧
是不是（x-y)(x+y)-(x+y)^2
=（x-y)(x+y)-(x+y)(x+y)
=(x+y)[x-y-(x+y)]
=-2y(x+y)
第二题
(x+y)^2+mx+my
=(x+y)(x+y)+m(x+y)
=(x+y)(x+y+m)
第三题
a(x-a)(x+y)^2-b(x-a)^2(x+y)
=a(x-a)(x+y)(x+y)-b(x-a)(x-a)(x+y)
=(x-a)(x+y)[a(x+y)-b(x-a)]

1：（x+y)(x+y)-(x+y)^2
=（x+y)[(x+y)-(x+y)]
=（x+y)*0
=0
2：(x+y)^2+mx+my
=(x+y)^2+m(x+y)
=(x+y)[(x+y)+m]
=(x+y)(x+y+m)
3： a(x-a)(x+y)^2-b(x-a)^2(x+y)
=(x-a)(x+y)[a(x+y)-b(x-a)]
=(x-a)(x+y)(ax+ay-bx+ab)
=(x-a)(x+y)[(a-b)x+ay+ab]

(x+y)(x+y)-(x+y)^2
=(x+y)^2-(x+y)^2
=0
(x+y))^2+mx+my
=(x+y)^2+m(x+y)
=(x+y)(x+y+m)
3： a(x-a)(x+y)^2-b(x-a)^2(x+y)
=(x-a)(x+y)[a(x+y)-b(x-a)]
=(x-a)(x+y)(ax+ay-bx+ab)
=(x-a)(x+y)[(a-b)x+ay+ab]

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