http://hiphotos.baidu.com/%C8%CB%BC%E4%B1%AF%BE%E7/pic/item/9a45b8f44d202641dcc474e7.jpghttp://hiphotos.baidu.com/%C8%CB%BC%E4%B1%AF%BE%E7/pic/item/bf6819c303c4817ab219a8e0.jpg怎么会看不清呢...................................另存为了肯定
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/30 01:25:14
![http://hiphotos.baidu.com/%C8%CB%BC%E4%B1%AF%BE%E7/pic/item/9a45b8f44d202641dcc474e7.jpghttp://hiphotos.baidu.com/%C8%CB%BC%E4%B1%AF%BE%E7/pic/item/bf6819c303c4817ab219a8e0.jpg怎么会看不清呢...................................另存为了肯定](/uploads/image/z/12711395-11-5.jpg?t=http%3A%2F%2Fhiphotos.baidu.com%2F%25C8%25CB%25BC%25E4%25B1%25AF%25BE%25E7%2Fpic%2Fitem%2F9a45b8f44d202641dcc474e7.jpghttp%3A%2F%2Fhiphotos.baidu.com%2F%25C8%25CB%25BC%25E4%25B1%25AF%25BE%25E7%2Fpic%2Fitem%2Fbf6819c303c4817ab219a8e0.jpg%E6%80%8E%E4%B9%88%E4%BC%9A%E7%9C%8B%E4%B8%8D%E6%B8%85%E5%91%A2...................................%E5%8F%A6%E5%AD%98%E4%B8%BA%E4%BA%86%E8%82%AF%E5%AE%9A)
http://hiphotos.baidu.com/%C8%CB%BC%E4%B1%AF%BE%E7/pic/item/9a45b8f44d202641dcc474e7.jpghttp://hiphotos.baidu.com/%C8%CB%BC%E4%B1%AF%BE%E7/pic/item/bf6819c303c4817ab219a8e0.jpg怎么会看不清呢...................................另存为了肯定
http://hiphotos.baidu.com/%C8%CB%BC%E4%B1%AF%BE%E7/pic/item/9a45b8f44d202641dcc474e7.jpg
http://hiphotos.baidu.com/%C8%CB%BC%E4%B1%AF%BE%E7/pic/item/bf6819c303c4817ab219a8e0.jpg
怎么会看不清呢...................................
另存为了肯定看得清...您试试= =|||
http://hiphotos.baidu.com/%C8%CB%BC%E4%B1%AF%BE%E7/pic/item/9a45b8f44d202641dcc474e7.jpghttp://hiphotos.baidu.com/%C8%CB%BC%E4%B1%AF%BE%E7/pic/item/bf6819c303c4817ab219a8e0.jpg怎么会看不清呢...................................另存为了肯定
20.C(0,q) 直线与抛物线联立 x=(1\2)x^2+px+q (1\2)x^2+(p-1)x+q=0 ∵OA=OB 即原点(0,0)为两根的中点.韦达定理得x1+x2=2(1-p)=0 ∴P=1 ∴y=(1\2)x^2+x+q
又∵BC‖X轴 B(q,0) A(-q,0) C(0,q)
y=(1\2)(x+1)^2+x+q-1\2 对称轴X=-1 ∴q=-2(BC被X=-1平分)
∴y=(1\2)x^2+x-2
(2)BC=2 D(k,k) S△DBC=1\2BC*H=2*1\2*|k+2|=|k+2| s=|k+2|(-2<k
看不清
1),假设A为(1,1)
算出P=1 Q=-1/2
Y=1/2X2+X-1/2
由上式 ,得B(-1/2,-1/2),A(1/2,1/2)C(-1/2,0)
K<0,S=1/4K
K>0,S=(1/2+K)平方/2