一元二次方程y²-5y-6=0 x(x+1)-5x=0 (x+2)(x-2)=1 8y²-2=4y (x-3)(x-2)=42 4(x-1)²-x+1=0
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![一元二次方程y²-5y-6=0 x(x+1)-5x=0 (x+2)(x-2)=1 8y²-2=4y (x-3)(x-2)=42 4(x-1)²-x+1=0](/uploads/image/z/1271284-52-4.jpg?t=%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8By%26%23178%3B-5y-6%3D0+x%28x%2B1%29-5x%3D0+%28x%2B2%29%28x-2%29%3D1+8y%26%23178%3B-2%3D4y+%28x-3%29%28x-2%29%3D42+4%28x-1%29%26%23178%3B-x%2B1%3D0)
一元二次方程y²-5y-6=0 x(x+1)-5x=0 (x+2)(x-2)=1 8y²-2=4y (x-3)(x-2)=42 4(x-1)²-x+1=0
一元二次方程y²-5y-6=0 x(x+1)-5x=0 (x+2)(x-2)=1 8y²-2=4y (x-3)(x-2)=42 4(x-1)²-x+1=0
一元二次方程y²-5y-6=0 x(x+1)-5x=0 (x+2)(x-2)=1 8y²-2=4y (x-3)(x-2)=42 4(x-1)²-x+1=0
.y²-5y-6=0
(y-6)(y+1)=0
y1=6 y2=-1
2.(x+2)(x-2)=1
x²-5=0
x1=√5 x2=-√5
3.8y²-2=4y
4y²-2y-1=0
Δ=4+16=20
y1=(1+√5)/4 y2=(1-√5)/4
4.(x-3)(x-2)=42
x²-5x-36=0
(x-9)(x+4)=0
x1=9 x2=-4
5.4(x-1)²-x+1=0
4x²-9x+5=0
(4x-5)(x-1)=0
x1=5/4 x2=1
1.y²-5y-6=0
(y-6)(y+1)=0
y1=6 y2=-1
2.(x+2)(x-2)=1
x²-5=0
x1=√5 x2=-√5
3.8y²-2=4y
4y²-2y-1=0
Δ=4+16=20
y1=(1+√5)/4 y2...
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1.y²-5y-6=0
(y-6)(y+1)=0
y1=6 y2=-1
2.(x+2)(x-2)=1
x²-5=0
x1=√5 x2=-√5
3.8y²-2=4y
4y²-2y-1=0
Δ=4+16=20
y1=(1+√5)/4 y2=(1-√5)/4
4.(x-3)(x-2)=42
x²-5x-36=0
(x-9)(x+4)=0
x1=9 x2=-4
5. 4(x-1)²-x+1=0
4x²-9x+5=0
(4x-5)(x-1)=0
x1=5/4 x2=1
请选为最佳答案,谢谢
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y=6或-1