在四边形ABCD中,AD∥BC,∠ABC=90°,AB=BC,E为AB上一点,AE=AD,且BF∥CD,AF⊥CE于F.连接DE交对角线AC于H.下列结论:①△ACD≌ACE;②AC垂直平分ED;③CE=2BF;④CE平分∠ACB.其中结论正确的是( )A、
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 20:07:21
![在四边形ABCD中,AD∥BC,∠ABC=90°,AB=BC,E为AB上一点,AE=AD,且BF∥CD,AF⊥CE于F.连接DE交对角线AC于H.下列结论:①△ACD≌ACE;②AC垂直平分ED;③CE=2BF;④CE平分∠ACB.其中结论正确的是( )A、](/uploads/image/z/1271874-66-4.jpg?t=%E5%9C%A8%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%AD%2CAD%E2%88%A5BC%2C%E2%88%A0ABC%3D90%C2%B0%2CAB%3DBC%2CE%E4%B8%BAAB%E4%B8%8A%E4%B8%80%E7%82%B9%2CAE%3DAD%2C%E4%B8%94BF%E2%88%A5CD%2CAF%E2%8A%A5CE%E4%BA%8EF%EF%BC%8E%E8%BF%9E%E6%8E%A5DE%E4%BA%A4%E5%AF%B9%E8%A7%92%E7%BA%BFAC%E4%BA%8EH%EF%BC%8E%E4%B8%8B%E5%88%97%E7%BB%93%E8%AE%BA%EF%BC%9A%E2%91%A0%E2%96%B3ACD%E2%89%8CACE%EF%BC%9B%E2%91%A1AC%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86ED%EF%BC%9B%E2%91%A2CE%3D2BF%EF%BC%9B%E2%91%A3CE%E5%B9%B3%E5%88%86%E2%88%A0ACB%EF%BC%8E%E5%85%B6%E4%B8%AD%E7%BB%93%E8%AE%BA%E6%AD%A3%E7%A1%AE%E7%9A%84%E6%98%AF%EF%BC%88%E3%80%80%E3%80%80%EF%BC%89A%E3%80%81)
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