在四边形ABCD中,对角线AC、BD相交于点O,设锐角∠DOC=α,将△DOC按逆时针方向旋转得到△D′OC′(0°<旋转角<90°)连接AC′、BD′,AC′与BD′相交于点M.(1)当四边形ABCD为矩形时,如图1,求证:
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![在四边形ABCD中,对角线AC、BD相交于点O,设锐角∠DOC=α,将△DOC按逆时针方向旋转得到△D′OC′(0°<旋转角<90°)连接AC′、BD′,AC′与BD′相交于点M.(1)当四边形ABCD为矩形时,如图1,求证:](/uploads/image/z/12755668-4-8.jpg?t=%E5%9C%A8%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%AD%2C%E5%AF%B9%E8%A7%92%E7%BA%BFAC%E3%80%81BD%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9O%2C%E8%AE%BE%E9%94%90%E8%A7%92%E2%88%A0DOC%3D%CE%B1%2C%E5%B0%86%E2%96%B3DOC%E6%8C%89%E9%80%86%E6%97%B6%E9%92%88%E6%96%B9%E5%90%91%E6%97%8B%E8%BD%AC%E5%BE%97%E5%88%B0%E2%96%B3D%E2%80%B2OC%E2%80%B2%EF%BC%880%C2%B0%EF%BC%9C%E6%97%8B%E8%BD%AC%E8%A7%92%EF%BC%9C90%C2%B0%EF%BC%89%E8%BF%9E%E6%8E%A5AC%E2%80%B2%E3%80%81BD%E2%80%B2%2CAC%E2%80%B2%E4%B8%8EBD%E2%80%B2%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9M.%EF%BC%881%EF%BC%89%E5%BD%93%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%BA%E7%9F%A9%E5%BD%A2%E6%97%B6%2C%E5%A6%82%E5%9B%BE1%2C%E6%B1%82%E8%AF%81%EF%BC%9A)
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