# include <stdio.h> main() { char s[]={"012xy"}; int i,n=0; for (i=0; s[i]!#include main(){ char s[]={“012xy”};int i,n=0;for(i=0;s[i]!=0;i++)if(s[i]>=’a’&&s[i]
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 18:30:27
![# include <stdio.h> main() { char s[]={"012xy"}; int i,n=0; for (i=0; s[i]!#include main(){ char s[]={“012xy”};int i,n=0;for(i=0;s[i]!=0;i++)if(s[i]>=’a’&&s[i]](/uploads/image/z/12777166-46-6.jpg?t=%23+include+%26lt%3Bstdio.h%26gt%3B+main%28%29+%7B+char+s%5B%5D%3D%7B%26quot%3B012xy%26quot%3B%7D%3B+int+i%2Cn%3D0%3B+for+%28i%3D0%3B+s%5Bi%5D%21%23include+main%28%29%7B+char+s%5B%5D%3D%7B%E2%80%9C012xy%E2%80%9D%7D%3Bint+i%2Cn%3D0%3Bfor%28i%3D0%3Bs%5Bi%5D%21%3D0%3Bi%2B%2B%29if%28s%5Bi%5D%3E%3D%E2%80%99a%E2%80%99%26%26s%5Bi%5D)
xՑJA_eBX
ݺ]w0/L3l5wB44KLPh0YEvf^ݤ.
颋N % #Lt0 (J̖́0= "pHev2IcWVw4r (,b4 +(ZW<nSN$P]oӈeXR0=cF;VN1yl㇡)!Wb 7GH*JZ|}'
3B(e)e9Q4n
it1HOXkP|^g\/¢`mL
# include <stdio.h> main() { char s[]={"012xy"}; int i,n=0; for (i=0; s[i]!#include main(){ char s[]={“012xy”};int i,n=0;for(i=0;s[i]!=0;i++)if(s[i]>=’a’&&s[i]
# include <stdio.h> main() { char s[]={"012xy"}; int i,n=0; for (i=0; s[i]!
#include
main()
{ char s[]={“012xy”};int i,n=0;
for(i=0;s[i]!=0;i++)
if(s[i]>=’a’&&s[i]
# include <stdio.h> main() { char s[]={"012xy"}; int i,n=0; for (i=0; s[i]!#include main(){ char s[]={“012xy”};int i,n=0;for(i=0;s[i]!=0;i++)if(s[i]>=’a’&&s[i]
要答案的话,把程序运行一下就知道拉.我觉得就是A,因为s[0]==0,当i==0时,s[i]!=0为假,跳出循环,此时n没变,仍是0.若是判断字符是否结束,判断条件应是:s[i]!='\0';