If the equation m(x-1)=2001-n(x-2) for x has infinite roots ,then m的2001次方+n的2001次方=(英汉小词典:equation方程,infinite roots 无数个根)
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If the equation m(x-1)=2001-n(x-2) for x has infinite roots ,then m的2001次方+n的2001次方=(英汉小词典:equation方程,infinite roots 无数个根)
If the equation m(x-1)=2001-n(x-2) for x has infinite roots ,then m的2001次方+n的2001次方=
(英汉小词典:equation方程,infinite roots 无数个根)
If the equation m(x-1)=2001-n(x-2) for x has infinite roots ,then m的2001次方+n的2001次方=(英汉小词典:equation方程,infinite roots 无数个根)
If the equation(方程) m(x-1)=2001-n(x-2) for x has infinite roots(无限个根) , then m的2001次方+n的2001次方= 0
因为X有无限个根,所以先令X=1,得出0=2001-n(-1),再令X=2,得出m=2001
所以m=2001,n=-2001.
所以m的2001次方+n的2001次方=0