what's the answer for this math problemDamped Harmonic MotionA bungee jumper plummets from a high bridge to the river below and then bounces back over and over again. At time t seconds after her jump, her height H (in yards) above the river is given

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what's the answer for this math problemDamped Harmonic MotionA bungee jumper plummets from a high bridge to the river below and then bounces back over and over again. At time t seconds after her jump, her height H (in yards) above the river is given
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what's the answer for this math problemDamped Harmonic MotionA bungee jumper plummets from a high bridge to the river below and then bounces back over and over again. At time t seconds after her jump, her height H (in yards) above the river is given
what's the answer for this math problem
Damped Harmonic MotionA bungee jumper plummets from a high bridge to the river below and then bounces back over and over again. At time t seconds after her jump, her height H (in yards) above the river is given by H(t)=124+85e-t/21cos(0.21π t) Find her height at the times indicated in the table.tH(t) 01.124.36.18.29.911.7Report answers accurate to at least 4 decimal places.

what's the answer for this math problemDamped Harmonic MotionA bungee jumper plummets from a high bridge to the river below and then bounces back over and over again. At time t seconds after her jump, her height H (in yards) above the river is given
说说我理解的大意吧：
就是从高桥往河面上做蹦极跳.
当蹦过t秒后,这个人距离河面的高度可以用这个公式来计算：H(t)=124+85e-t/21cos(0.21π t)
如表中所示找出她距离河面的高度 tH(t) 01.124.36.18.29.911.7
计算结果至少精确到小数点后四位.
我认为这道题你给的不全.

请说汉语 谢谢！

把这几个t的值代回到公式H(t)=124+85e-t/21cos(0.21π t)中就能求H了

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