若a^2-ab-12b^2=0,且b不得与0,求(2a-b)/(2a+b)的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 21:24:17
![若a^2-ab-12b^2=0,且b不得与0,求(2a-b)/(2a+b)的值](/uploads/image/z/12876978-66-8.jpg?t=%E8%8B%A5a%5E2-ab-12b%5E2%3D0%2C%E4%B8%94b%E4%B8%8D%E5%BE%97%E4%B8%8E0%2C%E6%B1%82%282a-b%29%2F%282a%2Bb%29%E7%9A%84%E5%80%BC)
x){ѽ41H71I()@Ɏ)IOv>7Ɏ>g4u4vY-O$铭WΆ2H6NH5IҴ5PSH5N&I`%(Zm5t͒\
'٦@)6`@ŖI@`:(`qؓ)<-l@ Ss
若a^2-ab-12b^2=0,且b不得与0,求(2a-b)/(2a+b)的值
若a^2-ab-12b^2=0,且b不得与0,求(2a-b)/(2a+b)的值
若a^2-ab-12b^2=0,且b不得与0,求(2a-b)/(2a+b)的值
(a+3b)(a-4b)=0 => a=-3b a=4b
(2a-b)/(2a+b)=(-6b-b)/(-6b+b)=-7b/(-5b)=7/5
(2a-b)/(2a+b)=(8b-b)/(8b+b)=7b/9b=7/9
∴ (2a-b)/(2a+b)的值为 7/5 或 7/9 .