作业帮cosπ/5=cos4π/5,
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cosπ/5=cos4π/5,
cosπ/5=cos4π/5,
cosπ/5=cos4π/5,
不对
cosπ/5=cos(-π/5)=cos(-π/5+2π)=cos(9π/5)
cosπ/5=cos4π/5,
cosπ/5 +cos2π/5 +cos3π/5 +cos4π/5 =可以简写.
求值:arccos(cos4/5π)=
cosπ/9*cos2π/9*cos4π/9=?
cosπ/7cos2/7πcos4/7π=
求cosπ/5乘cos2π/5乘cos3π/5乘cos4π/5
求值cosπ/5cos2π/5cos4π/5cos8π/5
sin5π/4cos4π/5tan11π/6sin乘cos乘tan
cos4π=?
-cos4/5π 是多少?用分式表示
比较cos4,cos4π/5,sin7/6π大小,大哥大姐们,帮帮俺啦.
比较cos4,cos4π/5,sin7π/6的大小如题 谢谢了
已知sin4次方-cos4次方=5/9,求cos4
cosπ/17cos2π/17cos4π/17cos8π/17=___
cosπ/7cos2π/7cos4π/7cos8π/7=?每步都写
cosπ/9cos2π/9cos3π/9cos4π/9=
急 、COSπ/9*COS2π/9*COS4π/9=?同样,
cosπ/7cos2π/7cos4π/7=?写下过程,谢谢~