sin(α -π/4)=7√2/10,cos2α =7/25,求sianα 及tan(α +π/3)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 11:13:26
xP10
c|)%8Ť: 8`g zYqc*3]S=? Wu-fk:>8/D!b沂2S^ AgX:ϣ!(q
fs;:JUbq qio|:)["s92
sin(α -π/4)=7√2/10,cos2α =7/25,求sianα 及tan(α +π/3)
sin(α -π/4)=7√2/10,cos2α =7/25,求sianα 及tan(α +π/3)
sin(α -π/4)=7√2/10,cos2α =7/25,求sianα 及tan(α +π/3)
cos2α =7/25=1-2sin^2a ,2sin^2a=1-7/25=18/25 ,sina=±3/5
sin(α -π/4)=(√2/2)(sina-cosa)=7√2/10 ,sina-cosa=7/5 ,cosa=4/5 ,tana=±3/4
tan(α +π/3)=(tana+tanπ/3)/(1-tanatanπ/3)
=(3/4+√3)/(1-3√3/4)或( -3/4+√3)/(1+3√3/4)
已知 sinα + cosα / sinα - cosα = 2 ,则 sin(α-5π) x sin(3π/2-α)等于A,3/4B,±3/10C,3/10D,-3/10
已知α∈(0,π/4),a=(sinα)^(cosα),b=(sinα)^(sinα),c=(cosα)^(sinα),则a、b、c的大小关系是
在三角形abc中,已知c=7,a=10,A=30°求角c以及S△ABC(精确到0.1.在三角形abc中,已知c=7,a=10,A=30°求角c以及S△ABC(精确到0.01)2.求最值:(1)y=sin(α+π/4)+sin(α-π/4)(2)y=6cosα+8sinα
设△ABC是锐角三角形a.b.c分别是内角A.B.C所对边长,并且sin^A=sin(π/3+B)sin(π/3-B)+sin^B.1.求角A的2.若向量AB*向量AC=12,a=2√7,求b,c(其中b<c)
在△ABC中,求证;sin^(A/2)+sin^(B/2)+sin^(C/2)=1-2sin(A/2)sin(B/2)sin(C/2)
已知sin(a-π/4)=7√2 ̄/10,cos 2α=7/25,求sinα及tan(α+π/3)
若sinα-cosα=-1/5,α∈(3/2π,7/4π),求sinα与cosα 若sin(α+β)=1/2,sin(α-β)=1/3,求log√5(ta若sinα-cosα=-1/5,α∈(3/2π,7/4π),求sinα与cosα 若sin(α+β)=1/2,sin(α-β)=1/3,求log√5(tan*cotβ)若sinα-2cosα/3sinα+5
求值:(tan10°-√3)×cos10°/sin50° 求证:[sin(2α+β)]/sinα- 2cos(α+β)=sinβ/cosα 化简cosθ+cos(θ+2π/3)+cos(θ+4π/3) 证明:sin(α+β)sin(α-β)=sin^2α-sin^2β
2sin(α+π/3)=sinα+______
sin0=0 sin(1/6π)=1/2sin(1/3π)=√3/2sin(1/2π)=1sin(2/3π)=√3/2sin(5/6π)=1/2sin(π)=0sin(-π)=0sin(-5/6π)=-1/2sin(-2/3π)=-√3/2sin(-1/2π)=-1sin(-1/3π)=-√3/2sin(-1/6π)=-1/2sin(7/6π)=-1/2sin(4/3π)=-√3/2sin(5/3π)=-√3/2sin(11/6π)=-1/
已知三角形ABC的三内角A,B,C所对应三边为a,b,c,且sin(π/4+A)=7√2/10,0
设△ABC是锐角三角形,a、b、c分别是内角A、B、C所对边长,并且sin²A=sin(π/3+B)并且sin²A=sin(π/3+B)*sinsin(π/3-B)+sin²B(2)若AB*AC=12,a=2√7,求b、c(其中b<c)
y=sinx+cosx可化成_____?A.2sin(x-π/4);B.2sin(x+π/4); C.√2sin(x-π/4);D.√2sin(x+π/4);
还是两道函数题1.已知sin(α-π/4)=7√2/10,cos2α=7/25,求sinα及tan(α+π/3)2.已知cosα-cosβ=1/2,sinα-sinβ=1/3,求cos(α-β)的值
若cos2α/sin(α+7/4×π)=-√2/2,则cosα+sinα的值
若cos2α/sin(α-π/4)=-√2/2,则cosα+sinα的值为?
若cos2α/sin(α-π/4)=-√2/2,则cosα+sinα的值为?
已知A+b+C=π 求证 cosA+cosB+cosC=1+4sin(A/2)sin(B/2)sin(C/2)