落x-(1/x)=2 则x^2+1/(x^2^)=

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落x-(1/x)=2 则x^2+1/(x^2^)=
x){1ao=t)

落x-(1/x)=2 则x^2+1/(x^2^)=
落x-(1/x)=2 则x^2+1/(x^2^)=

落x-(1/x)=2 则x^2+1/(x^2^)=
因为x-(1/x)=2,所以等式两边平方有:
x^2-2+(1/x)^2=4
所以x^2+1/(x^2^)=4+2=6

x-(1/x)=2 平方得x^2+1/(x^2)-2=4,则x^2+1/(x^2)=4+2=6

x²+1/x²=(x-1/x)²+2=2²+2=6

已知式左右同时平方得x^2+1/(x^2^)-2=4
所以x^2+1/(x^2^)=6

x-(1/x)=2
两边平方 得
x^2+1/(x^2)-2=4
x^2+1/(x^2)=6
题多带了一个符号^