f(n)=1/n+1 + 1/n+2 + 1/n+3 +……+1/3n,则f(k+1)-f(k)=

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f(n)=1/n+1 + 1/n+2 + 1/n+3 +……+1/3n,则f(k+1)-f(k)=
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f(n)=1/n+1 + 1/n+2 + 1/n+3 +……+1/3n,则f(k+1)-f(k)=
f(n)=1/n+1 + 1/n+2 + 1/n+3 +……+1/3n,则f(k+1)-f(k)=

f(n)=1/n+1 + 1/n+2 + 1/n+3 +……+1/3n,则f(k+1)-f(k)=
f(k+1)-f(k)=1/(3k+1) + 1/(3k+2)+ 1/(3k+3)- 1/(k+1)=1/(3k+1) + 1/(3k+2)- 2/(3k+3)>0