| 5 6 -3||-1 0 1|| 1 2 1|求矩阵特征值和特征向量|λE-A|=(λ-2)^3故特征值λ1=λ2=λ3=2对应于 λ=2的特征向量满足(λE-A)X=0,即|-3 -6 3| |x1| |0||1 2 -1| |x2|=|0||-1 -2 1| |x3| |0|对系数矩阵作初等行变换得|1 2 -1||
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 03:05:05
![| 5 6 -3||-1 0 1|| 1 2 1|求矩阵特征值和特征向量|λE-A|=(λ-2)^3故特征值λ1=λ2=λ3=2对应于 λ=2的特征向量满足(λE-A)X=0,即|-3 -6 3| |x1| |0||1 2 -1| |x2|=|0||-1 -2 1| |x3| |0|对系数矩阵作初等行变换得|1 2 -1||](/uploads/image/z/12892502-38-2.jpg?t=%7C+5+6+-3%7C%7C-1+0+1%7C%7C+1+2+1%7C%E6%B1%82%E7%9F%A9%E9%98%B5%E7%89%B9%E5%BE%81%E5%80%BC%E5%92%8C%E7%89%B9%E5%BE%81%E5%90%91%E9%87%8F%7C%CE%BBE-A%7C%3D%EF%BC%88%CE%BB-2%EF%BC%89%5E3%E6%95%85%E7%89%B9%E5%BE%81%E5%80%BC%CE%BB1%3D%CE%BB2%3D%CE%BB3%3D2%E5%AF%B9%E5%BA%94%E4%BA%8E+%CE%BB%3D2%E7%9A%84%E7%89%B9%E5%BE%81%E5%90%91%E9%87%8F%E6%BB%A1%E8%B6%B3%28%CE%BBE-A%29X%3D0%2C%E5%8D%B3%7C-3+-6+3%7C+%7Cx1%7C+%7C0%7C%7C1+2+-1%7C+%7Cx2%7C%3D%7C0%7C%7C-1+-2+1%7C+%7Cx3%7C+%7C0%7C%E5%AF%B9%E7%B3%BB%E6%95%B0%E7%9F%A9%E9%98%B5%E4%BD%9C%E5%88%9D%E7%AD%89%E8%A1%8C%E5%8F%98%E6%8D%A2%E5%BE%97%7C1+2+-1%7C%7C)
xN@_en#wd`^z
E>5HxPjEOmˉWp[
nnggv3먙4E(B)dJ|ݷs2x!Cz=Um]MGma2v-Y-21ȶ45.\7}MJRbR(D)s['TVGZOt|=0vUn3$A ͟4DHDo\pf;)2Y?-Uzez,ؠ̰