若函数y=sin wx * cos wx (w>0)的最小正周期为4π,则常数w=A 1/4B 1/2C 2D 4

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若函数y=sin wx * cos wx (w>0)的最小正周期为4π,则常数w=A 1/4B 1/2C 2D 4
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若函数y=sin wx * cos wx (w>0)的最小正周期为4π,则常数w=A 1/4B 1/2C 2D 4
若函数y=sin wx * cos wx (w>0)的最小正周期为4π,则常数w=
A 1/4
B 1/2
C 2
D 4

若函数y=sin wx * cos wx (w>0)的最小正周期为4π,则常数w=A 1/4B 1/2C 2D 4
because :2sinx*cosx=sin2x
so,y=1/2sin2wx
T= 4π,
so,2w = 2π/4 π,
so,w=1/4
so,the answer is A
i dont know why i cant tape the chinese in the end .
but i also want you can use my answer thank you.im also a high school student.

原式=sin(2wx)/2
最小正周期为4π
2π/2w=4π
2w=1/2
w=1/4

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