1/2=1-1/2,1/6=1/2-1/3,1/12=1/3-1/4,⋯请根据上面算式中的规律,完成下面算式的运算.1/2+1/6+1/12+1/20+1/30+1/42+1/56
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1/2=1-1/2,1/6=1/2-1/3,1/12=1/3-1/4,⋯请根据上面算式中的规律,完成下面算式的运算.1/2+1/6+1/12+1/20+1/30+1/42+1/56
1/2=1-1/2,1/6=1/2-1/3,1/12=1/3-1/4,⋯请根据上面算式中的规律,完成下面算式的运算.
1/2+1/6+1/12+1/20+1/30+1/42+1/56
1/2=1-1/2,1/6=1/2-1/3,1/12=1/3-1/4,⋯请根据上面算式中的规律,完成下面算式的运算.1/2+1/6+1/12+1/20+1/30+1/42+1/56
(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6)+(1/6-1/7)+(1/7-1/8)
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8
=1-1/8
=7/8
解
原式
=(1-1/2)+(1/2-1/3)+……+(1/7-1/8)
=1+(1/2-1/2)+(1/3-1/3)+……+(1/7-1/7)-1/8
=1-1/8
=7/8
C语言S=2-1/4+1/6-1/8…-1/2n之和
1、(x-2)平方-6(x-2)+10=1
1*1/2=?
1+1=2?
1+1=2?
1+1×2=?
2-1=1
计算(1-1/50)(1-1/49)(1-1/48).(1-1/4)(1-1/3)(1-1/2)=?
2+1+2+6=
Sn=1/(2^2-1)+1/(4^2-1)+1/(6^2-1)+.+1/[(2n)^2-1]求和
已知1/2×3=1/2-1/3,计算:1+1/2×3+1/3×4+1/4×5+1/5×6
1+2+1+2+1+2+1+2+1+2+1+2+1+2 =( )*( ) =()
巧算:(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)*(1/2+1/3+1/4+1/5)(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)*(1/2+1/3+1/4+1/5)=====
2【1/3x-1/2(x-1)+2】-1/2=x
(1-1/2)+(1-1/6)+(1-1/12)+...+(1-1/110)=?
1-1/2+1/3-1/4+1/5-1/6+1/7.-1/50=?
智慧闯关“计算”2分之1+6分之1+12分之1+20分之1+30分之142分之1/这个不是分之(提示:2分之1=1-2分之1,6分之1=2×3/1=2分之1-3分之1,12分之1=3×4/1=3分之1-4分之1..)
1×3+1=4=2^22×4+1=9=3^23×5+1=16=4^24×6+1=25=5^2……第n个算式可以表示为什么(-1)-(-1)^2+(-1)^3-(-1)^4+…-(-1)^100=第一题要结果,