在等差数列{an}中,已知a4是a2,a8的等比中项,且a3+1是a2,a6的等差中项 (1)求数列{an}的通项公式an 【已求为an=n】(2)数列{bn}满足:对任意的n∈N*,a1/b1+a2/b2+……+an/bn=2-(n+2)/2^n都成立①求数列{bn
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![在等差数列{an}中,已知a4是a2,a8的等比中项,且a3+1是a2,a6的等差中项 (1)求数列{an}的通项公式an 【已求为an=n】(2)数列{bn}满足:对任意的n∈N*,a1/b1+a2/b2+……+an/bn=2-(n+2)/2^n都成立①求数列{bn](/uploads/image/z/13162715-35-5.jpg?t=%E5%9C%A8%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%7Ban%7D%E4%B8%AD%2C%E5%B7%B2%E7%9F%A5a4%E6%98%AFa2%2Ca8%E7%9A%84%E7%AD%89%E6%AF%94%E4%B8%AD%E9%A1%B9%2C%E4%B8%94a3%2B1%E6%98%AFa2%2Ca6%E7%9A%84%E7%AD%89%E5%B7%AE%E4%B8%AD%E9%A1%B9+%EF%BC%881%EF%BC%89%E6%B1%82%E6%95%B0%E5%88%97%EF%BD%9Ban%EF%BD%9D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8Fan+%E3%80%90%E5%B7%B2%E6%B1%82%E4%B8%BAan%3Dn%E3%80%91%EF%BC%882%EF%BC%89%E6%95%B0%E5%88%97%7Bbn%7D%E6%BB%A1%E8%B6%B3%3A%E5%AF%B9%E4%BB%BB%E6%84%8F%E7%9A%84n%E2%88%88N%2A%2Ca1%2Fb1%2Ba2%2Fb2%2B%E2%80%A6%E2%80%A6%2Ban%2Fbn%3D2-%28n%2B2%29%2F2%5En%E9%83%BD%E6%88%90%E7%AB%8B%E2%91%A0%E6%B1%82%E6%95%B0%E5%88%97%7Bbn)
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