已知3+XY-2y=0(x≠0,Y≠0)求x/y-y/x-x+y/xy
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已知3+XY-2y=0(x≠0,Y≠0)求x/y-y/x-x+y/xy
已知3+XY-2y=0(x≠0,Y≠0)求x/y-y/x-x+y/xy
已知3+XY-2y=0(x≠0,Y≠0)求x/y-y/x-x+y/xy
x/y-y/x-x+y/xy = x-y/xy-x+y/xy =-2 y/xy =-2y/x 因为3x+XY-2y=0 所以3(x/y)+x/y-2=0 所以x/y=-1或2/3 所以原式=2或-3