A={x︱x²-2x-8<0}B={x︱x²+2x-3>0},C={x︱x²-3ax+2a²
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 02:33:14
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A={x︱x²-2x-8<0}B={x︱x²+2x-3>0},C={x︱x²-3ax+2a²
A={x︱x²-2x-8<0}B={x︱x²+2x-3>0},C={x︱x²-3ax+2a²
A={x︱x²-2x-8<0}B={x︱x²+2x-3>0},C={x︱x²-3ax+2a²
因为A={x︱x²-2x-8<0} B={x︱x²+2x-3>0}
所以A={-2<x<4﹜ B=﹛x<-3或 x>1﹜ 所以 A∩B=﹛1<x<4﹜
因为C={x︱x²-3ax+2a²