-cos(2x-π/3) x∈[-π,π] 求值域

cos（π/3+x）+cos（π/3-x） cos(-x-2π) 和cos(π-x) 化简 化简cos(π/2-x)cos(π/2+x)cot(π-x)/sin(3π/2+x)cos(3π+x)tan(π+x) 化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π) 化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π) 证明:函数f(x)=cos^2+cos^2(x+π/3)+cos^2(x-π/3)是常数函数 cos (π/3-2x) 求导 y=cos(π/3-x)cos[π/2（x-1)]判断奇偶性y=cos(π/3-x)cos(π/3+x)判断奇偶性 x∈（0,π/2）sin(x)+cos(x)=tan(x),x的范围? 已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 化简f(x)=cos(2x-π/3)-cos2x f(x)=2(cosx)^3+sin(360°-x)^2-cos(180°-x)-3/2+2cos(180°+x)+cos(-x)求f(π/3) 已知函数f(x)=cos(2x-π/3)+sin(^2)x+cos(^2)x.求化简～ f(x) = cos(2x-π/3) + sin^2x - cos^2x的对称轴方程 为什么cos(2x-π/3)-sin(5π/6) =cos(2x-π/3)? 化简cos(2π/3-x)+cos(2π/3+x)+cosx 三角函数运算 为什么 cos2x+cos( 4π/3 -2x)=cos( π/3 +2x) 函数y=cos(3π/2-x)/cos(3π-x)最小正周期是