已知cot(π/4+θ)=3则(2sinθ-cosθ)/(cosθ+2sinθ)=?

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已知cot(π/4+θ)=3则(2sinθ-cosθ)/(cosθ+2sinθ)=?
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已知cot(π/4+θ)=3则(2sinθ-cosθ)/(cosθ+2sinθ)=?
已知cot(π/4+θ)=3则(2sinθ-cosθ)/(cosθ+2sinθ)=?

已知cot(π/4+θ)=3则(2sinθ-cosθ)/(cosθ+2sinθ)=?
cot(π/4+θ)=3
tan(π/4+θ)=1/3=(tanπ/4+tanθ)/(1-tanπ/4tanθ)
tanθ=-1/2
(2sinθ-cosθ)/(cosθ+2sinθ)
=(2tanθ-1)/(1+2tanθ)
=-2/0
分母为0,答案不存在啊

cot(π/4+θ)=3
tan(π/4+θ)=1/3=(tanπ/4+tanθ)/(1-tanπ/4tanθ)
tanθ=-1/2
(2sinθ-cosθ)/(cosθ+2sinθ)
=(2tanθ-1)/(1+2tanθ)
=-2/0
哈哈,抄的,不介意吧