求函数y=sin^4xcosx+sinxcos^4x(0

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求函数y=sin^4xcosx+sinxcos^4x(0
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求函数y=sin^4xcosx+sinxcos^4x(0
求函数y=sin^4xcosx+sinxcos^4x
(0

求函数y=sin^4xcosx+sinxcos^4x(0
sinXcosX(sin^3x+cos^3x)=sinxcosx(sinx+cosx)(sin^2x+cos^2x-sinxcosx) 设sinx+cosx=y 所以 sinxcosx=(y^2-1)/2 原式=(y^2-1)(3-y^2)y/4 又因为y=

y=sin5x
0<5x<5派/2
-1<=y<=1
最大值是1