已知函数f(x)=1/3mx^2-(2+m/2)x^2+4x+1,g(x)=mx+5,1).当m≥4时,求函数f(x)的单调递增区间(2).是否存在m<0,使得对任意的x1,x2∈[2,3]都有f(x1)-g(x2)≤1,若存在,求m的范围,若不存在,请说明理由
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![已知函数f(x)=1/3mx^2-(2+m/2)x^2+4x+1,g(x)=mx+5,1).当m≥4时,求函数f(x)的单调递增区间(2).是否存在m<0,使得对任意的x1,x2∈[2,3]都有f(x1)-g(x2)≤1,若存在,求m的范围,若不存在,请说明理由](/uploads/image/z/13331265-33-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D1%2F3mx%5E2-%282%2Bm%2F2%29x%5E2%2B4x%2B1%2Cg%28x%29%3Dmx%2B5%2C1%29.%E5%BD%93m%E2%89%A54%E6%97%B6%2C%E6%B1%82%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4%282%29.%E6%98%AF%E5%90%A6%E5%AD%98%E5%9C%A8m%EF%BC%9C0%EF%BC%8C%E4%BD%BF%E5%BE%97%E5%AF%B9%E4%BB%BB%E6%84%8F%E7%9A%84x1%EF%BC%8Cx2%E2%88%88%5B2%2C3%5D%E9%83%BD%E6%9C%89f%28x1%29-g%28x2%29%E2%89%A41%2C%E8%8B%A5%E5%AD%98%E5%9C%A8%EF%BC%8C%E6%B1%82m%E7%9A%84%E8%8C%83%E5%9B%B4%EF%BC%8C%E8%8B%A5%E4%B8%8D%E5%AD%98%E5%9C%A8%EF%BC%8C%E8%AF%B7%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1)
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