(1)(2x²-7x+5)+(3x-1)-(x²-1) (2)x-3(1-2x+x²)+3(-2+3x-x²) (3)3a+二分之一(a-6b)-三(4)5a+(-2a)+{a+1+(2a+a)+[a+1-(a+3)]}
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/21 10:41:26
![(1)(2x²-7x+5)+(3x-1)-(x²-1) (2)x-3(1-2x+x²)+3(-2+3x-x²) (3)3a+二分之一(a-6b)-三(4)5a+(-2a)+{a+1+(2a+a)+[a+1-(a+3)]}](/uploads/image/z/1333381-13-1.jpg?t=%281%29%282x%26%23178%3B-7x%2B5%29%2B%283x-1%29-%28x%26%23178%3B-1%29+%282%29x-3%281-2x%2Bx%26%23178%3B%29%2B3%28-2%2B3x-x%26%23178%3B%29+%283%293a%2B%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%80%28a-6b%29-%E4%B8%89%284%295a%2B%28-2a%29%2B%EF%BD%9Ba%2B1%2B%282a%2Ba%29%2B%5Ba%2B1-%28a%2B3%29%5D%EF%BD%9D)
xQMJCAJ@>'~,"
H,<W;nfMic4Lsr*C;Fs[c~ۭn*ǡo
:y[خugM~Y1yaI9RI;126D?5^/pĺ9ʔ75,˘;!ͷW;nXFM}~&F]lSf A`Ǡ >KE#
fЭ曧E|=۾"K1lЦ= H
(1)(2x²-7x+5)+(3x-1)-(x²-1) (2)x-3(1-2x+x²)+3(-2+3x-x²) (3)3a+二分之一(a-6b)-三(4)5a+(-2a)+{a+1+(2a+a)+[a+1-(a+3)]}
(1)(2x²-7x+5)+(3x-1)-(x²-1) (2)x-3(1-2x+x²)+3(-2+3x-x²) (3)3a+二分之一(a-6b)-三
(4)5a+(-2a)+{a+1+(2a+a)+[a+1-(a+3)]}
(1)(2x²-7x+5)+(3x-1)-(x²-1) (2)x-3(1-2x+x²)+3(-2+3x-x²) (3)3a+二分之一(a-6b)-三(4)5a+(-2a)+{a+1+(2a+a)+[a+1-(a+3)]}
(1)(2x²-7x+5)+(3x-1)-(x²-1)
=2x^2-7x+5+3x-1-x^2+1
=x^2-4x+5
(2)x-3(1-2x+x^2)+3(-2+3x-x^2)
=x-3+6x-3x^2-6+9x-3x^2
=-6x^2+16x-9
(3)3a+1/2(a-6b)-3
=3a+1/2a-3b-3
=7/2a-3b-3
(4)5a+(-2a)+{a+1+(2a+a)+[a+1-(a+3)]}
=3a+(4a+1+a+1-a-3)
=3a+4a-1
=7a-1
1. 2x 2;-7x+5 = 0 2 -5 1 -1 (2x-5)(x-1) = 0 , x = 5/2 , 1 2. 怎么有个Y? 3. (2x-3) 2;-2x+3 = 0 (2x-