用公式法解下列方程(m²-n²)x²-4mnx=m²-n²(m²-n²≠0)
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![用公式法解下列方程(m²-n²)x²-4mnx=m²-n²(m²-n²≠0)](/uploads/image/z/1333640-56-0.jpg?t=%E7%94%A8%E5%85%AC%E5%BC%8F%E6%B3%95%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%EF%BC%88m%26%23178%3B-n%26%23178%3B%EF%BC%89x%26%23178%3B-4mnx%3Dm%26%23178%3B-n%26%23178%3B%EF%BC%88m%26%23178%3B-n%26%23178%3B%E2%89%A00%EF%BC%89)
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用公式法解下列方程(m²-n²)x²-4mnx=m²-n²(m²-n²≠0)
用公式法解下列方程(m²-n²)x²-4mnx=m²-n²(m²-n²≠0)
用公式法解下列方程(m²-n²)x²-4mnx=m²-n²(m²-n²≠0)
因为m²-n²≠0,所以是二元一次方程.用求根公式解决如下:
http://www.jyeoo.com/math/ques/detail/63404b65-4c7c-49f1-92fc-aff5d9b8ef58
绝对正确 带解析