三角形内角和应用题如图,已知:∠A= 1/2∠ABC = 1/2∠C,BD平分∠ABC,求∠DBC的度数(列式解答~!)
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三角形内角和应用题如图,已知:∠A= 1/2∠ABC = 1/2∠C,BD平分∠ABC,求∠DBC的度数(列式解答~!)
三角形内角和应用题
如图,已知:∠A= 1/2∠ABC = 1/2∠C,BD平分∠ABC,求∠DBC的度数
(列式解答~!)
三角形内角和应用题如图,已知:∠A= 1/2∠ABC = 1/2∠C,BD平分∠ABC,求∠DBC的度数(列式解答~!)
∵∠A+∠ABC+∠C=180°
又∵∠A= 1/2∠ABC = 1/2∠C
∴1/2∠ABC+∠ABC+∠ABC=180°
∴∠ABC=72°
∵BD平分∠ABC
∴∠ABD=∠CBD=1/2∠ABC=36°
∵∠A+∠ABC+∠C=180°
又∵∠A= 1/2∠ABC = 1/2∠C
∴1/2∠ABC+∠ABC+∠ABC=180°
∴∠ABC=72°
∵BD平分∠ABC
∴∠ABD=∠CBD=1/2∠ABC=36°
∵∠A+∠ABC+∠C=180°
又∵∠A= 1/2∠ABC = 1/2∠C
∴1/2∠ABC+∠ABC+∠ABC=180°
∴∠ABC=72°
∵BD平分∠ABC
∴∠ABD=∠CBD=1/2∠ABC=36°
∵∠A+∠ABC+∠C=180°
又∵∠A= 1/2∠ABC = 1/2∠C
∴1/2∠ABC+∠ABC+∠ABC=180°
∴∠ABC=72°
∵BD平分∠ABC
∴∠ABD=∠CBD=1/2∠ABC=36°
∵∠A+∠ABC+∠C=180°
又∵∠A= 1/2∠ABC = 1/2∠C
∴1/2∠ABC+∠ABC+∠ABC=180°
∴∠ABC=72°
∵BD平分∠ABC
∵∠A= 1/2∠ABC = 1/2∠C
∴∠ABC=∠C=2∠A
∵∠A+∠ABC +∠C=180°
∴∠A+2∠A+2∠A=180°
∴∠A=36°
∵BD平分∠ABC
∴∠DBC=1/2∠ABC
∴∠DBC=∠A=36°