3sinx-√3cosx=2√3sin(x+φ),φ∈(-π,π),则φ的值是?-π/6.
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3sinx-√3cosx=2√3sin(x+φ),φ∈(-π,π),则φ的值是?-π/6.
3sinx-√3cosx=2√3sin(x+φ),φ∈(-π,π),则φ的值是?
-π/6.
3sinx-√3cosx=2√3sin(x+φ),φ∈(-π,π),则φ的值是?-π/6.
当X=0时,有3*sin0-√3cos0=2√3sin(0+φ),-√3=2√3sinφ
sinφ=-1/2 又φ∈(-π,π)所以φ=-π/6.
别忘了给悬赏分哦
3sinx-√3cosx=√3(√3sinx-cosx)
=2√3【(cosπ/6)sinx-sin(π/6)cosx】
=2√3sin(x-π/6)
-π/6或5π/6
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