在△ABC中,∠ACB=90°,CD⊥AB,E为AC的中点,ED.CB延长线交于一点F,求证:AC*DF=BC*CF
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![在△ABC中,∠ACB=90°,CD⊥AB,E为AC的中点,ED.CB延长线交于一点F,求证:AC*DF=BC*CF](/uploads/image/z/13356456-24-6.jpg?t=%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0ACB%3D90%C2%B0%2CCD%E2%8A%A5AB%2CE%E4%B8%BAAC%E7%9A%84%E4%B8%AD%E7%82%B9%2CED.CB%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4%E4%BA%8E%E4%B8%80%E7%82%B9F%2C%E6%B1%82%E8%AF%81%EF%BC%9AAC%2ADF%3DBC%2ACF)
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