作业帮计算（^2-2x+5)^2-2(^2-2x+5)(x^2-2x-3）+（x^2-2x-3)^2=[( )-( )]^2=?
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/08 21:04:24
![计算（^2-2x+5)^2-2(^2-2x+5)(x^2-2x-3）+（x^2-2x-3)^2=[( )-( )]^2=?](/uploads/image/z/133612-52-2.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%88%5E2-2x%2B5%29%5E2-2%28%5E2-2x%2B5%29%28x%5E2-2x-3%EF%BC%89%2B%EF%BC%88x%5E2-2x-3%29%5E2%3D%5B%28+%29-%28+%29%5D%5E2%3D%3F)
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计算（^2-2x+5)^2-2(^2-2x+5)(x^2-2x-3）+（x^2-2x-3)^2=[( )-( )]^2=?
计算（^2-2x+5)^2-2(^2-2x+5)(x^2-2x-3）+（x^2-2x-3)^2=[( )-( )]^2=?
计算（^2-2x+5)^2-2(^2-2x+5)(x^2-2x-3）+（x^2-2x-3)^2=[( )-( )]^2=?
（x^2-2x+5)^2-2(x^2-2x+5)(x^2-2x-3）+（x^2-2x-3)^2
=[(x^2-2x+5 )-( x^2-2x-3)]^2
=(5+3)²
=64