√2x/5-√2x-3.6/5=0.2 这道题怎么计算得出x?

来源:学生作业帮助网 编辑:作业帮 时间:2024/12/01 03:58:49
√2x/5-√2x-3.6/5=0.2 这道题怎么计算得出x?
x){1˨BTL)?e䗋f]YK

√2x/5-√2x-3.6/5=0.2 这道题怎么计算得出x?
√2x/5-√2x-3.6/5=0.2 这道题怎么计算得出x?

√2x/5-√2x-3.6/5=0.2 这道题怎么计算得出x?
√2x/5-√2x-3.6/5=0.2
4√2x/5-3.6/5=0.2
4√2x-3.6=0.2 *5=1
4√2x=1+3.6=4.6
x=4.6/(4√2)=0.8132

说明:不好意思,抄楼上的。
√2x/5-√2x-3.6/5=0.2
-4√2x/5-3.6/5=0.2
-4√2x-3.6=0.2 *5=1
-4√2x=1+3.6=4.6
x=-4.6/(4√2)=-0.8132

去分母合并同类项得 -4√2x=4.6
√2x=-1.15
x=-115√2/200

x5
√2x-5√2x-3.6=1
-4√2x=4.6
x=

xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 y=(3x^2-x√x+5√x-9)/√x 求导 求极限 F(x)=(5x-7)/(2x+√x) x趋于无穷 √2x/5-√2x-3.6/5=0.2 这道题怎么计算得出x? 已知1/√(x)+√(x)=√5,求√(x/x2+x+1)+√(x/x2-x+1)的值定义域 x>0,两边平方,x+2+1/x=5,x+1/x=3,x^2-3x+1=0,x^2+x+1-4x=0,x^2+x+1=4x,x^2-x+1-2x=0.x^2-x+1=2x,√[x/(x^2+x+1)]-√[x/(x^2-x+1)]=√[x/(4x)]-√[x/2x]=√(1/4)-√(1/2) x-√2=5x(√2-x) x-√2=5x(√2-x) (√x-2)+x-y-(√2-x)=5 y=(√x+x^5+sinx)/x^2 求导 若x=√2,求代数式[(x^2-2x+4)/(√x^2-4x+4)]/[(x^3+8)/(x^2-4)]*[|6-x|/(x^2-5x-6)-[1/(x^2-x+1)]^-1的值 √(3)x+5=2x y=(3x^2-x√x+5√x-9)/√x 求导我算到4.5x^0.5-1+2x+4.5x^1.5 , *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || xy²/(x²y) - y×x²/(x²+x)=(x²-3x)/(x²-5x×2x) - 10/(x²-6x+9)=2a/(a²-4) - 1/(a-2)=2/(1-a ) - 1/(a-1)=x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? 帮个忙 求你们了 急用xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 求这三道题的值域f(x)=x^2+4x+5 x∈{2.5} f(x)=x^2-4x+5 x∈{1.5} f(x)=x+√1-x 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x