已知二次函数f(x)=ax2+bx满足f(1-x)=f(1+x),且方程f(x)=x有两相等实根(1)求f(x)的解析式已知二次函数f(x)=ax2+bx(a≠0,a、b为常数)满足f(1-x)=f(1+x),且方程f(x)=x有两相等实
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 12:07:24
![已知二次函数f(x)=ax2+bx满足f(1-x)=f(1+x),且方程f(x)=x有两相等实根(1)求f(x)的解析式已知二次函数f(x)=ax2+bx(a≠0,a、b为常数)满足f(1-x)=f(1+x),且方程f(x)=x有两相等实](/uploads/image/z/13396281-33-1.jpg?t=%E5%B7%B2%E7%9F%A5%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dax2%2Bbx%E6%BB%A1%E8%B6%B3f%EF%BC%881-x%EF%BC%89%3Df%EF%BC%881%2Bx%EF%BC%89%2C%E4%B8%94%E6%96%B9%E7%A8%8Bf%EF%BC%88x%EF%BC%89%3Dx%E6%9C%89%E4%B8%A4%E7%9B%B8%E7%AD%89%E5%AE%9E%E6%A0%B9%EF%BC%881%EF%BC%89%E6%B1%82f%EF%BC%88x%EF%BC%89%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E5%B7%B2%E7%9F%A5%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dax2%2Bbx%EF%BC%88a%E2%89%A00%2Ca%E3%80%81b%E4%B8%BA%E5%B8%B8%E6%95%B0%EF%BC%89%E6%BB%A1%E8%B6%B3f%EF%BC%881-x%EF%BC%89%3Df%EF%BC%881%2Bx%EF%BC%89%2C%E4%B8%94%E6%96%B9%E7%A8%8Bf%EF%BC%88x%EF%BC%89%3Dx%E6%9C%89%E4%B8%A4%E7%9B%B8%E7%AD%89%E5%AE%9E)
xWRF~t+,əE.ȕ4L{#&(H18ޅz%sW跻'Ӌ{w~Ǚq`g*TiԯԧL3緫#&U.[nzBl6Zߜ0uVs[{vwκ(шWv6[لC|gRp{&tk[k U'dDfy;s+P5
/ЅwP 5Z`+uv+.FSNy~@я̚Т+ENJ