5 x²+2y²+2xy-14x-10y+17=0求x,y请用初中知识5 x²+2y²+2xy-14x-10y+17=0求x、y

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5 x²+2y²+2xy-14x-10y+17=0求x,y请用初中知识5 x²+2y²+2xy-14x-10y+17=0求x、y
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5 x²+2y²+2xy-14x-10y+17=0求x,y请用初中知识5 x²+2y²+2xy-14x-10y+17=0求x、y
5 x²+2y²+2xy-14x-10y+17=0求x,y
请用初中知识
5 x²+2y²+2xy-14x-10y+17=0求x、y

5 x²+2y²+2xy-14x-10y+17=0求x,y请用初中知识5 x²+2y²+2xy-14x-10y+17=0求x、y
5 x^2+2y^2+2xy-14x-10y+17
=(x^2+y^2+2xy-6x-6y+9)+(4x^2-8x+4)+(y2-4y+4)
=(x+y-3)^2+4(x-1)^2+(y-2)^2=0
所以x+y-3=0
x-1=0
y-2=0
所以x=1,y=2

怎么算啊这个：X²+4X+Y²-2Y+5=0 则X²+Y²=?²²²²²²²²²²²²X²+4X+Y²-2Y+5X=0 则X²+Y²=? 1.y²-5xy-6x² 2.m²-3mn+2n² 已知x² -XY = 2,Y² -XY= 5,求x² - 4x Y+ Y² = 2x² + xY -3Y² = x² 已知x² -XY = 2,Y² -XY= 5,求x² - 4x Y+ Y² = 2x² + xY -3Y² = x² + xY- 2Y² =求x² - 4x Y+ Y² = 在线求助完全平方公式因式分解(1)-a²-1+2a(2)2x²y-x²-xy²(3)4x²-20x+25(4)(x²+1)²-4x²(5)(2x-y)²-2(2x-y)+1(6)(x+y)²-2(x²-y²)+(x-y)² 谢谢高手解答x²-xy=2,-xy+y²=5求x²-2xy+ y²,x²- y² （3x-y）²-（2x+y）²+5y² 若x²+xy-2y²=0,则x²+3xy+y²/x²+y² x²+xy-2y²=0则x²+3xy+y²/x²+y² x/y=2,求x²-3xy+y²/2x²-3xy+5y² 已知x²+4x+y²-2y+5=0,则x²+y²= x²-2xy+y²-9 （x+y）²-2(x²-y²)+（y-x）² 分解公因式 （x+y）²-2（x²-y²）+（x-y）² 因式分解：x²-y²-z²+2yz 因式分解 x²-2xy+y²-z² 把（2z²-2x²-2y²)²-16x²y²因式分解 计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy a²-ab+ac-bc2ax-10ay+5by-bx3ax+4by+4ay+3bxm²+5m-mn-5nx²-y²+ax+aya²-2ab+b²-c²x³+x²y-xy²-y³4a²-b²+6a-3b9m²-6m+2n-n²x²-y²-z²+2yzx³-x²y-xy²+y³