log2^(log2^5x)=1 求x看不明白可以看图.

log2^(log2^5x)=1 求x看不明白可以看图. log4(log2^x)=log2(log4^x)求log2^x log2 (x+1)+log2 x=log6 log2[log2/1(log2x)]=0 求 x 解2log2^(x-5)=log2^(x-1)+1 log2^(x^log2^x)=? log2(x)=-1 log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 log2^x-1=0,求x log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) 求反函数y=log2(x+1) y=log2^(x+1)求反函数 求反函数:y=log2(x-1) 求函数的定义域 y=log2(x^2-5x+6)+log2(x+2/x-1) 已知log2(x^2)=log2(根号2-1)-log2(根号2+1),求x+1/x y=1+log2^x/2+(log2^x)^2的值域log2^x=t 求反解法做