若x²+xy-2x+y=0,y²+xy+x-2y=0,求x+y的值
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若x²+xy-2x+y=0,y²+xy+x-2y=0,求x+y的值
若x²+xy-2x+y=0,y²+xy+x-2y=0,求x+y的值
若x²+xy-2x+y=0,y²+xy+x-2y=0,求x+y的值
若x²+xy-2x+y=0,y²+xy+x-2y=0,
相加,得
x²+2xy+y²-x-y=0
(x+y)²-(x+y)=0
(x+y)(x+y-1)=0
所以
x+y=0或x+y=1
若x²+xy-2x+y=0,y²+xy+x-2y=0,
相加,得
x²+2xy+y²-x-y=0
(x+y)²-(x+y)=0
(x+y)(x+y-1)=0
所以
x+y=0或x+y=1
所以x+y=0或x+y=1
望采纳!谢谢!
算了下,0或者2.