3X-2y-[-4x+(y+3x)]-(2x-3y)其中|x+1|+(y+2分之1)的平方=0 先化简在求值3X-2y-[-4x+(y+3x)]-(2x-3y)其中|x+1|+(y+2分之1)的平方=0 先化简在求值
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3X-2y-[-4x+(y+3x)]-(2x-3y)其中|x+1|+(y+2分之1)的平方=0 先化简在求值3X-2y-[-4x+(y+3x)]-(2x-3y)其中|x+1|+(y+2分之1)的平方=0 先化简在求值
3X-2y-[-4x+(y+3x)]-(2x-3y)其中|x+1|+(y+2分之1)的平方=0 先化简在求值
3X-2y-[-4x+(y+3x)]-(2x-3y)其中|x+1|+(y+2分之1)的平方=0 先化简在求值
3X-2y-[-4x+(y+3x)]-(2x-3y)其中|x+1|+(y+2分之1)的平方=0 先化简在求值3X-2y-[-4x+(y+3x)]-(2x-3y)其中|x+1|+(y+2分之1)的平方=0 先化简在求值
|x+1|+(y+2分之1)的平方=0
x+1=0
y+2分之1=0
x=-1
y=-2分之1
3X-2y-[-4x+(y+3x)]-(2x-3y)
=3X-2y-(-4x+y+3x)-2x+3y
=3X-2y+4x-y-3x-2x+3y
=(3+4-3-2)x+(-2-1+3)y
=2x
=2*(-1)
=-2
3X-2y-[-4x+(y+3x)]-(2x-3y)
=3x-2y-[-4x+y+3x]-2x+3y
=x+y-[-x+y]
=x+y+x-y
=2x
|x+1|+(y+1/2)^2=0,所以 x=-1 y=-1/2
解得2x=-2
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