高二数列有道解题看不懂已知数列a1=1,an=a(n-1)/3a(n-1)+1(n>=2)设bn=ana(n+1),求数列{an}的通项公式求数列{bn}的前n项和snAn=[A(n-1)]/[3A(n-1)+1]==> 1/An =3 +1/A(n-1)==> {1/an}为等差数列,首项 =1/A1 =1,公差 =31/An =1/A
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![高二数列有道解题看不懂已知数列a1=1,an=a(n-1)/3a(n-1)+1(n>=2)设bn=ana(n+1),求数列{an}的通项公式求数列{bn}的前n项和snAn=[A(n-1)]/[3A(n-1)+1]==> 1/An =3 +1/A(n-1)==> {1/an}为等差数列,首项 =1/A1 =1,公差 =31/An =1/A](/uploads/image/z/13443345-9-5.jpg?t=%E9%AB%98%E4%BA%8C%E6%95%B0%E5%88%97%E6%9C%89%E9%81%93%E8%A7%A3%E9%A2%98%E7%9C%8B%E4%B8%8D%E6%87%82%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97a1%3D1%2Can%3Da%28n-1%29%2F3a%28n-1%29%2B1%28n%3E%3D2%29%E8%AE%BEbn%3Dana%28n%2B1%29%2C%E6%B1%82%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%E6%B1%82%E6%95%B0%E5%88%97%7Bbn%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CsnAn%3D%5BA%28n-1%29%5D%2F%5B3A%28n-1%29%2B1%5D%3D%3D%3E+1%2FAn+%3D3+%2B1%2FA%28n-1%29%3D%3D%3E+%7B1%2Fan%7D%E4%B8%BA%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2C%E9%A6%96%E9%A1%B9+%3D1%2FA1+%3D1%2C%E5%85%AC%E5%B7%AE+%3D31%2FAn+%3D1%2FA)
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