高二数列有道解题看不懂已知数列a1=1,an=a(n-1)/3a(n-1)+1(n>=2)设bn=ana(n+1),求数列{an}的通项公式求数列{bn}的前n项和snAn=[A(n-1)]/[3A(n-1)+1]==> 1/An =3 +1/A(n-1)==> {1/an}为等差数列,首项 =1/A1 =1,公差 =31/An =1/A
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