作业帮若log2^3×log3^4×log4^x=log9^3 ,求x
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若log2^3×log3^4×log4^x=log9^3 ,求x
若log2^3×log3^4×log4^x=log9^3 ,求x
若log2^3×log3^4×log4^x=log9^3 ,求x
log2^3×log3^4×log4^x=log9^3
(lg3/lg2)×(lg4/lg3)×(lgx/lg4)=log9^(9^1/2)
所以lgx/lg2=1/2
lgx=1/2*lg2=lg√2
x=√2
log2^3×log3^4×log4^x=log9^3
2log4^x=1/2
log4^x=1/4
x=4^1/4
x=√2
log2 20---log2 5+log3 4 * log4 3 等于什么
（log2 3+log4 27）(log3 4+log27 16)
若log2^3×log3^4×log4^x=log9^3 ,求x
求值：(log4(3)+log8(3))(log3(2)+log3(4))-log2(64)
log2(20)-log2(5)+2log3(2)×log4(3)
若a=log2 3,b=log3 2,c=log4 6比较大小
(log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了
[log3（4）+log根下3（2）][log2(9)+log4(根3)]
运用对数换底公式化简log2(3)*log3(4)*log4(5)*log5(2),
log2 3 · log3 4 ·log4 5 ·log5 2 前面的是底数
log2(3)*log3(4)*log4(5)*log5(6)*log6(7)*log7(8)=?
帮忙换底化简下列:logaC*logcA .log2 3 * log3 4 * log4 5 * log5 2
求值：3^(log3 (25) )+(-C(5,4)^(log2 1)+16^(log4(2sin(π/2))=
log2(3)+log3(4)+log4(5)+log5(6)+log6(7)+log7(8)
若log2[log3(log4)]=0,求x
(log2 5+log4 125)log3 2/ log根号3 5
log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9
log2(3)*log3(4)*log4(5)*.log(k+1)(k+2)=log2(k+2) 怎么证