[(x+y)²-(x+y)(x+3y)-5y²]÷(2y) 其中x=-2,y=½
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[(x+y)²-(x+y)(x+3y)-5y²]÷(2y) 其中x=-2,y=½
[(x+y)²-(x+y)(x+3y)-5y²]÷(2y) 其中x=-2,y=½
[(x+y)²-(x+y)(x+3y)-5y²]÷(2y) 其中x=-2,y=½
[(x+y)²-(x+y)(x+3y)-5y²]÷(2y)
=[x²+2xy+y²-(x²+4xy+9y²)-5y²]÷(2y)
=(-13y²-2xy)÷(2y)
=-(13y+2x)/2
将x=-2,y=½代入原式=-(13/2-2×2)/2=-5/4
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