因式分解a^2-b^2+4a-2b+3已知答案a^2-b^2+4a-2b+3 =a^2+4a+4-b^2-2b-1 =(a+2)^2-(b+1)^2 =(a+2+b+1)(a+2-b-1) =(a+b+3)(a-b+1)=(a+2)^2-(b+1)^2 =(a+2+b+1)(a+2-b-1)
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![因式分解a^2-b^2+4a-2b+3已知答案a^2-b^2+4a-2b+3 =a^2+4a+4-b^2-2b-1 =(a+2)^2-(b+1)^2 =(a+2+b+1)(a+2-b-1) =(a+b+3)(a-b+1)=(a+2)^2-(b+1)^2 =(a+2+b+1)(a+2-b-1)](/uploads/image/z/1349277-69-7.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3a%5E2-b%5E2%2B4a-2b%2B3%E5%B7%B2%E7%9F%A5%E7%AD%94%E6%A1%88a%5E2-b%5E2%2B4a-2b%2B3+%3Da%5E2%2B4a%2B4-b%5E2-2b-1+%3D%28a%2B2%29%5E2-%28b%2B1%29%5E2+%3D%28a%2B2%2Bb%2B1%29%28a%2B2-b-1%29+%3D%28a%2Bb%2B3%29%28a-b%2B1%29%3D%28a%2B2%29%5E2-%28b%2B1%29%5E2+%3D%28a%2B2%2Bb%2B1%29%28a%2B2-b-1%29)
因式分解a^2-b^2+4a-2b+3已知答案a^2-b^2+4a-2b+3 =a^2+4a+4-b^2-2b-1 =(a+2)^2-(b+1)^2 =(a+2+b+1)(a+2-b-1) =(a+b+3)(a-b+1)=(a+2)^2-(b+1)^2 =(a+2+b+1)(a+2-b-1)
因式分解a^2-b^2+4a-2b+3
已知答案a^2-b^2+4a-2b+3
=a^2+4a+4-b^2-2b-1
=(a+2)^2-(b+1)^2
=(a+2+b+1)(a+2-b-1)
=(a+b+3)(a-b+1)
=(a+2)^2-(b+1)^2
=(a+2+b+1)(a+2-b-1)
因式分解a^2-b^2+4a-2b+3已知答案a^2-b^2+4a-2b+3 =a^2+4a+4-b^2-2b-1 =(a+2)^2-(b+1)^2 =(a+2+b+1)(a+2-b-1) =(a+b+3)(a-b+1)=(a+2)^2-(b+1)^2 =(a+2+b+1)(a+2-b-1)
这是平方差公式啊,看成2个整体
a^2-b^2=(a+b)(a-b)
a²-b² =(a+b)(a-b)
把题中的(a+2)和(b+1)看成一个整体
从而得出结论
=(a+2)^2-(b+1)^2
=(【a+2】+【b+1】)(【a+2】-【b+1】)
=(a+b+3)(a-b+1)
另a+2=x,b+1=y
x^2-y^2=(x+y)(x-y).这是定理公式
所以就(a+2+b+1)(a+2-b+1)
解释:(a+2)^2-(b+1)^2
根据平方差公式:a^2-b^2=(a+b)*(a-b)
所以=【(a+2)-(b+1)】【(a+2)+(b+1)】=(a+2+b+1)(a+2-b-1)