22x-x^2=72念出来就是 22x-x的平方=72 x为两个根 分别是多少

来源:学生作业帮助网 编辑:作业帮 时间:2024/08/04 13:36:52
22x-x^2=72念出来就是 22x-x的平方=72 x为两个根 分别是多少
xSJ@ XcRtѕ0#)֤&RU"Bu_p: >p# {0,e5dN >^ע+mD VUhO[E+Vi>62]ʚ,Ľ2%C98Bd=65rH,5crB2<I:΄X ?dfBlx l!7cWD!8Px-YAxK<ec( ´nIvJ)dnmg-nqL`P>:l/t (IjjKbO* :ړ"Xyaߕ1`5c0n()7P,},&h>)nV; vZg?2]_$:ÛޜjnNw

22x-x^2=72念出来就是 22x-x的平方=72 x为两个根 分别是多少
22x-x^2=72
念出来就是 22x-x的平方=72 x为两个根 分别是多少

22x-x^2=72念出来就是 22x-x的平方=72 x为两个根 分别是多少
22x-x^2=72
x平方-22x+72=0
(x-4)(x-18)=0
x=4或x=18

x² + 22x + 72 = 0
x² + 22x + 72 - 72 = 0 - 72. This is because we want to isolate the variables.
x² + 22x = -72
Take half of the x term and square it. * Because (a+b)² ...

全部展开

x² + 22x + 72 = 0
x² + 22x + 72 - 72 = 0 - 72. This is because we want to isolate the variables.
x² + 22x = -72
Take half of the x term and square it. * Because (a+b)² = a² + 2ab + b²
Then add it to both sides.
x² + 22x + 121 = -72+121
x² + 22x + 121 = 49
(x + 11)² = 49
Square root both sides
x + 11 = ±7
x + 11 = 7 and x + 11 = -7
Ans. x = -4, x = -18

收起

(22x-x)*2=72
所以x² + 22x + 121 = 49
(x + 11)² = 49
x + 11 = ±7
x + 11 = 7 and x + 11 = -7
x = -4, x = -18

(X-4)(X-18)=0
X1=4,X2=18