已知fx=sin²(x+π/4),若a=f(lg5),b=f(lg1/5),则 A.a+b=0已知fx=sin²(x+π/4),若a=f(lg5),b=f(lg1/5),则A.a+b=0 B.a-b=0 C.a+b=1 D.a-b=1
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![已知fx=sin²(x+π/4),若a=f(lg5),b=f(lg1/5),则 A.a+b=0已知fx=sin²(x+π/4),若a=f(lg5),b=f(lg1/5),则A.a+b=0 B.a-b=0 C.a+b=1 D.a-b=1](/uploads/image/z/13556058-42-8.jpg?t=%E5%B7%B2%E7%9F%A5fx%3Dsin%26%23178%3B%28x%EF%BC%8B%CF%80%EF%BC%8F4%29%2C%E8%8B%A5a%3Df%EF%BC%88lg5%EF%BC%89%2Cb%3Df%EF%BC%88lg1%EF%BC%8F5%EF%BC%89%2C%E5%88%99+A.a%2Bb%3D0%E5%B7%B2%E7%9F%A5fx%3Dsin%26%23178%3B%28x%EF%BC%8B%CF%80%EF%BC%8F4%29%2C%E8%8B%A5a%3Df%EF%BC%88lg5%EF%BC%89%2Cb%3Df%EF%BC%88lg1%EF%BC%8F5%EF%BC%89%2C%E5%88%99A.a%2Bb%3D0+B.a-b%3D0+C.a%2Bb%3D1+D.a-b%3D1)
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